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Syntax Error On Token Else Delete This Token Java

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Feynman diagram and uncertainty Is the partition function of non-conformal theories on a torus modular invariant? Every time I type in "else" it gives me the error "Syntax error on token, "else," Delete this token" I've been watching videos and I'm really trying to get a leg Please try to arrange them using {}. Thanks! weblink

Using any of these is going to earn you an error: IF, If, ELSE, Else All good with your spelling and capitalization? Okay, on to the next check. You can use that to shorten your code: else ("scissors".equalsIgnoreCase(theanswer));{ // likewise for the others What do you mean guard? Report message to a moderator Re: Else Error (Total newcomer) [message #1003613 is a reply to message #1001355] Mon, 21 January 2013 16:03 David KerberMessages: 100Registered: July 2009 public class WhoWins { Pickrps picked = new Pickrps(); String theanswer = picked.getAnswer(); void whowon(){ if ("rock".equals(theanswer)||"Rock".equals(theanswer));{ System.out.println("rock"); } else if ("paper".equals(theanswer)||"Paper".equals(theanswer));{ System.out.println("paper"); } else ("scissors".equals(theanswer)||"Scissors".equals(theanswer));{ System.out.println("scissors"); } } }

Syntax Error On Token Else Delete This Token Eclipse

That statement can be another "if", which is what I think you want: else if ("scissors".equals(theanswer)||"Scissors".equals(theanswer));{Also, are you aware of method equalsIgnoreCase? more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed total_tool_22 over 2 years ago it says unexpected identifier for me and i dont know what that means? Lol We are learning from Blue Pelican Java.

At first you are absolutly right about the fact that else does not need a condition! SCJP 1.4 - SCJP 6 - SCWCD 5 - OCEEJBD 6 - OCEJPAD 6 How To Ask Questions How To Answer Questions Post Reply Bookmark Topic Watch Topic New Topic You have a semicolon after the if statement. Error On Else Processing Maybe the solution is right in my face.

asked 3 years ago viewed 9269 times active 2 years ago Related 4576JavaScript function declaration syntax: var fn = function() {} vs function fn() {}2Learning Python else syntax error-2Syntax error at Syntax Error On Token Else While Expected Ask a question usually answered in minutes! permalinkembedsaveparentgive gold[–]TheFlyingGerbil0[S] 0 points1 point2 points 2 years ago(1 child)What about that last else statement? This is the full error message: Exception in thread "main" java.lang.Error: Unresolved compilation problem: Syntax error on token "else", delete this token at calculatorApplet.main(calculatorApplet.java:42) I wrote this code: import java.util.Scanner; import

Page generated in 0.03953 seconds .:: Contact :: Home ::. Syntax Error, "insert Else Statement To Complete Ifstatement" You can only upload photos smaller than 5 MB. Pointing them out might seem very elementary to experienced programmers. I hope this is a helpful comment! 1171 points Submitted by Mark about 3 years ago 25 Comments Judy about 3 years ago Thanks mrman, I'm sure some of the learners

Syntax Error On Token Else While Expected

Because I've followed the instruction and still not getting it. Specfically, swap lines 5 and 6, 13 and 14, and 21 and 22 and it should work. Syntax Error On Token Else Delete This Token Eclipse You helped me figure out what I was doing wrong! Syntax Error On Token Delete This Token Eclipse schauerlichNovember 11th, 2009, 10:19 PMThere's a semicolon after the if statement.

The grammar is if ( condition ) expression-or-block { else expression-or-block } Since ; is an empty expression, this works for an if clause and nothing happens in the then clause have a peek at these guys I only needed that final semi-colon after the last closing brace, not the ones after the else if closing brace. 275 points Submitted by Obinna Ugwu about 1 year ago ⌂HomeMailSearchNewsSportsFinanceCelebrityWeatherAnswersFlickrMobileMore⋁PoliticsMoviesMusicTVGroupsStyleBeautyTechShoppingInstall Outlet w/3 neutrals, 3 hots, 1 ground? SCJP 1.4 - SCJP 6 - SCWCD 5 - OCEEJBD 6 - OCEJPAD 6 How To Ask Questions How To Answer Questions Jesper de Jong Java Cowboy Saloon Keeper Posts: Syntax Error On Token Else Delete This Token Android

Remnants of the dual number more hot questions lang-java about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts As the scanner object hasn't been created, the first three if statements will come back false and your else statement will be printed (regardless of whether the input password was correct). When you put a semicolon at the end of a condition, like this: if (choice1 === choice2); you are telling the interpreter to consider that as the end of your if check over here Note how the { }, ( ) and ; are used.

System.out.println("TRUE"); } else { // Will never print FALSE System.out.println("FALSE"); } So using what we have just learned about the == operator and the equals() method we can use this within Syntax Error Else Python It worked, this is totally different from what I am learning to do. The idea is that on the IF and IF-ELSE lines, you have handled most conditions.

Indentation levels for the first and last line in your application shouldn't differ.

In the particular code example above, if the program execution has reached the else statement it means that: a < b returned false and a > b also returned false. This is syntactically incorrect. haxor789 over 2 years ago You probably ended a conditional statement too early by a semicolon or in an other way have a look at the post below this one. Syntax Error On Token Expected Please help me resolve my problem :D public class If { public static void main(String args[]){ int test = 6; if (test == 9); System.out.println("Yes"); }else{ <--Error Here System.out.println("This is else");

The users who voted to close gave this specific reason:"This question was caused by a problem that can no longer be reproduced or a simple typographical error. You then come out of the if statement and declare a brand new option variable before the code I provided above. Click here to learn more. this content Good sources are also MDN+javaScript command or stackoverflow.

What do you do with all the bodies? I want my code to be a calculator so if you guys can fix my code to not conflict with the math operations. Outlet w/3 neutrals, 3 hots, 1 ground? if ("rock".equals(theanswer)||"Rock".equals(theanswer));{ // ... } This must be: // Note, no semi-colon after the statement!

more hot questions lang-java about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation Science Other permalinkembedsavegive goldaboutblogaboutsource codeadvertisejobshelpsite rulesFAQwikireddiquettetransparencycontact usapps & toolsReddit for iPhoneReddit for Androidmobile websitebuttons<3reddit goldredditgiftsUse of this site constitutes acceptance of our User Agreement and Privacy Policy (updated). © 2016 reddit inc. I guess in Java it's more often called the condition. share|improve this answer answered Oct 8 '14 at 11:13 ToYonos 6,31121531 add a comment| Not the answer you're looking for?

For example: System.out.println("Please Enter Your Bank Pin."); Scanner userInput = new Scanner (System.in); int number; int password = 7123; int amount = 4000; int option; number = userInput.nextInt(); if (number == Instead of a { to start that block, you have put a semicolon at the end of that first line. Have a look at the code below // Create two Strings with the same text "abc" String obj1 = new String("abc"); String obj2 = new String("abc"); // Compare the two String As others have already pointed out, you haven't properly closed one or more if/else statements ( see my previous post ).

Is there a performance difference in the 2 temp table initializations? Trenton Turner almost 3 years ago you rock!! Count your brackets. Now I know why!!! 0 votes permalink @Mark: The error you explained is also caused by this only-one-statement-after-a-conditional-case-rule.

But the error in the code is not that else has "condition" but that there are two statements on one line (without separator): else (a == b) { do something different; I paste the code in an online editor and it comes up with a page, How do you make it a website? 6 answers More questions Write a simple c++ program And like you said for those with experience some things are clear to see but to the beginners it can be a nightmare but once you get it, its great. labs.codecademy.com where you can test code that you think should be running without the requirements of an exercise.

You qualify for a credit card.") } ; else ; { (creditCheck < 100) ; return ("Alas you do not qualify for a credit card.